(0,05x^2-0,1x)+3000=5000

Solution for (0,05x^2-0,1x)+3000=5000 equation:

(0.05x^2-0.1x)+3000=5000

We move all terms to the left:

(0.05x^2-0.1x)+3000-(5000)=0

We add all the numbers together, and all the variables

(0.05x^2-0.1x)-2000=0

We get rid of parentheses

0.05x^2-0.1x-2000=0

a = 0.05; b = -0.1; c = -2000;
Δ = b2-4ac
Δ = -0.12-4·0.05·(-2000)
Δ = 400.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.1)-\sqrt{400.01}}{2*0.05}=\frac{0.1-\sqrt{400.01}}{0.1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.1)+\sqrt{400.01}}{2*0.05}=\frac{0.1+\sqrt{400.01}}{0.1}
$